Question

If the volume of a certain mass of gas at a temperature of 27 ° C and pressure of 380mm Hg is 50m3, what will be the volume of that gas in STP?​

Answer 1

Answer:

STP is usually given as 273.15 K (0°C) and 1 atm.

The combined gas law can be used to answer this question. The formula is:

P1·V1/T1 = P2·V2/T2, where;

P1 = initial pressure = 1 atm

V1 = 27.3 cm^3

T1 = initial temperature 273.15 K

P2 = final pressure = ?

V2 = final temperature = 27.3 cm^3

T2 = 27°C + 273.15 = 300 K = 3.0×10^2 K to represent two significant figures

Rearrange the formula to isolate P2. Insert the known values and solve.

P2 = (P1·V1·T2)/(V2·T1)

P2 = (1 atm·27.3 cm^3·3.0×10^2 K)/(27.3 cm^3·273.15 K) = 1.1 atm to two significant figures

The pressure required is 1.1 atm.

Answer 2

Answer:

Hey mate,

☆Given That is

STP is usually given as 273.15k amd 1 atm

Formula is

P1×V1/T1=P2×V2/T2

P1=1atm

V1=27.3cm^3

T1=273.15k

P2=?

V2=27.3cm^3

T2=300k

P2=(P1×V1×T2)/V2×T1

Then arranging all the terms we get pressure = 1.1atm

Hope it helps u mate

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