Question

If the volume of a
cone of
of height gan
find the diameter of its
right sie cisculas
is 487cm?
of its base
12cm
lo cm
6 cm
8 cm ​

Answer 1

Answer:

8

Step-by-step explanation:

Given: h=9cm

Given: h=9cmLet radius =r

Given: h=9cmLet radius =r⇒Volume=48π=

Given: h=9cmLet radius =r⇒Volume=48π= 3

Given: h=9cmLet radius =r⇒Volume=48π= 31

Given: h=9cmLet radius =r⇒Volume=48π= 31

Given: h=9cmLet radius =r⇒Volume=48π= 31 πr

Given: h=9cmLet radius =r⇒Volume=48π= 31 πr 2

Given: h=9cmLet radius =r⇒Volume=48π= 31 πr 2 h

Given: h=9cmLet radius =r⇒Volume=48π= 31 πr 2 h⇒

Given: h=9cmLet radius =r⇒Volume=48π= 31 πr 2 h⇒ 3

Given: h=9cmLet radius =r⇒Volume=48π= 31 πr 2 h⇒ 31

Given: h=9cmLet radius =r⇒Volume=48π= 31 πr 2 h⇒ 31

Given: h=9cmLet radius =r⇒Volume=48π= 31 πr 2 h⇒ 31 πr

Given: h=9cmLet radius =r⇒Volume=48π= 31 πr 2 h⇒ 31 πr 2

Given: h=9cmLet radius =r⇒Volume=48π= 31 πr 2 h⇒ 31 πr 2 ×9

Given: h=9cmLet radius =r⇒Volume=48π= 31 πr 2 h⇒ 31 πr 2 ×9 3

Given: h=9cmLet radius =r⇒Volume=48π= 31 πr 2 h⇒ 31 πr 2 ×9 3 =48π

Given: h=9cmLet radius =r⇒Volume=48π= 31 πr 2 h⇒ 31 πr 2 ×9 3 =48π⇒r

Given: h=9cmLet radius =r⇒Volume=48π= 31 πr 2 h⇒ 31 πr 2 ×9 3 =48π⇒r 2

Given: h=9cmLet radius =r⇒Volume=48π= 31 πr 2 h⇒ 31 πr 2 ×9 3 =48π⇒r 2 =16,r=4

Given: h=9cmLet radius =r⇒Volume=48π= 31 πr 2 h⇒ 31 πr 2 ×9 3 =48π⇒r 2 =16,r=4⇒Diameter =2×4=8cm

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