If the volume of a cube is 3√3a³ , then find the total surface area of the cube.
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let the side of the cube = s units
volume of the cube = s³ cubic units -------- ( i )
Total surface area = 6s² square units ------ ( ii )
According to the problem ,
1 ) volume of the cube = 3√3 a³ = √3 × √3 ×√3 a³ = ( √3 a )³ ---- ( iii )
( i ) = ( iii )
s³ = ( √3 a )³
Therefore ,
s = √3 a units
2 ) Total Surface Area of the cube = 6s² [ from ( ii ) ]
TSA = 6 × ( √3 a )²
= 6 × ( √3a ) × ( √3a )
= 6 × 3 × a²
= 18a² square units
Therefore,
side of the cube = s= √3 a units
TSA = 18a² square units
PLEASE MARK MY ANSWER AS A BRAINLIEST.
volume of the cube = s³ cubic units -------- ( i )
Total surface area = 6s² square units ------ ( ii )
According to the problem ,
1 ) volume of the cube = 3√3 a³ = √3 × √3 ×√3 a³ = ( √3 a )³ ---- ( iii )
( i ) = ( iii )
s³ = ( √3 a )³
Therefore ,
s = √3 a units
2 ) Total Surface Area of the cube = 6s² [ from ( ii ) ]
TSA = 6 × ( √3 a )²
= 6 × ( √3a ) × ( √3a )
= 6 × 3 × a²
= 18a² square units
Therefore,
side of the cube = s= √3 a units
TSA = 18a² square units
PLEASE MARK MY ANSWER AS A BRAINLIEST.
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