Question

If the volume of a cube is 729m^3. Find its surface area.

Answer 1

$volume \: of \: cube \: = 729 \: {m}^{3} \\ {side}^{3} = 729 \: \\ side = \sqrt[3]{729} \\ side \: = 9 \: m \\ \\ surface \: area \: of \: cube \: = 6 {a}^{2} \\ = 6 ({9}^{2} ) \\ 6 \times 81 \\ 486 \: {m}^{2}$
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