Question

If the volume of a cuboid is given equal to p(x)=5x^3-3x^2-14x, then it's possible dimensions are

Answer 1

Answer:

5x^3-3x^2-14x=0

x(5x^2-3x-14)=0

5x^2-3x-14=0/x

5(x−2)(x+1.4)=0

(x-2)(x+1.4)=0/5

(x-2)(x+1.4)=0

As x cannot be negative so its possible dimension can be 2.

Answer 2

Question:

 If the volume of a cuboid is given equal to p(x)=5x^3-3x^2-14x, then it's possible dimensions are

Given:

The volume of the cuboid is given by the polynomial p(x) = 5x^3 - 3x^2 - 14x

To Find:

• Dimensions?

Solution:

→ 5x^3 - 3x^2 - 14x = 0

(let be the 'x' common)

→ x(5x^2 - 3x - 14) = 0

→ 5x^2 - 3x - 14 = 0/x

→ 5(x - 2)(x + 1.4) = 0

→ (x - 2)(x + 1.4) = 0/5

→ (x - 2)(x + 1.4) = 0

As x cannot be negative so its possible dimension can be 2.