Question

if the volume of a fixed amount of an ideal gas is doubled while its temperature is quadrupled Then
the pressure
(A) Remains the same
(C) Decreases by a factor of 4
(8) Decreases by a factor of 2
(D) Increases by a factor of 2​

Answer 1

Answer ⇒ Increases by a Factor of 2.

Explanation ⇒ Let the Initial pressure be P, Initial volume be V and Initial temperature be T.

Then,  PV = nRT

Also, Final Volume = 2V, Final Temperature = 4T. Let Final pressure be P'.

Then,

P'(2V) = nR(4T)

∴ P'V = 2(nRT)

∴ P'V = 2(PV)

∴ P' = 2P

Hence, the pressure becomes double.

Hence, Option (D). IS CORRECT.

Hope it helps.