If the volume of a gas collected at 60 ᵒC and 1 x 10⁵ Pa pressure was 70 cm³, what would be the volume at a temperature of 0 ᵒC and a pressure of 4 x 10⁵ Pa? Show all working and don't forget the units on your final answer.
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Answer:
14.3 cm³ or 14.3×10⁻³ L
Explanation:
According to standard gas equation,
P₁V₁/T₁ = P₂V₂/T₂
Convert degree Celcius to Kelvin scale.
Kelvin= °C+273
60°C:
=60+273
=333 K
0°C:
=0+273
=273 K
And also, convert cm³ to Litres.
1cm³ = 10⁻3 L
70cm³ = 70 * 10⁻³ L
Now, put these values in the Standard gas equation.
1 x 10⁵ × 70 × 10⁻³/333 = 4 x 10⁵ × V₂/273
V₂ = 1 x 10⁵ × 70 × 10⁻³ × 273 / 333 × 4 x 10⁵
V₂ = 14.3 × 10⁻³ L
or, 14.3 cm³
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