Question

If the volume of a gas collected at a temperature of 600 °C and pressure of 1.05 x 105 Nm-2 is
60 dm3 what would be the volume of gas at STP (P=1.01 X 103 Nm-2, T = 273 K)?​

Answer 1

S O L U T I O N :

Given:

⇝ Initial Pressure $\sf(P_1)$

⇝ Initial Volume $\sf(V_1)$

⇝ Final Volume $\sf(V_2)$

We know that,

• ❏ Boyle's law of gases states that at constant temperature the pressure of a gas is inversely proportional to its Volume.

$\begin{gathered} \sf \implies \: P \: \: \: \alpha \: \: \: \frac{1}{V} \\ \\ \end{gathered}$

$\begin{gathered} \sf \implies \: P_{1}V_{1} = P_{2}V _{2} \\ \\ \sf \implies \: (152)(50) = P_{2}(30) \\ \\ \sf \implies \: P _{2} = \frac{150 \times 50}{30} \\ \\ \implies \: \sf{ \large{ \: P _{2} = 250 \: cm \: Hg.}}\end{gathered}$

❏ Hence, the pressure of the gas would be 250 cm Hg(a).