Question

If the volume of a gas collected at a temperature of 60°C and pressure of 1.05×105 Nm-2 is 60dm3 what would be the volume of gas at STP (P = 1.01×103Nm–2, T = 273K)?

Answer 1

• by using the formula P1V1/T1 = P2V2/T2
• V2 = P1V1T2/P2T1
• Here P1 = 1.01×103Nm^2; P2 = 1.05×105Nm^2; V1 = 60dm^3 convert into litres ; T1=273K; T2=60+273 = 330K
• Then substitute the values in the given formula then we get the answer

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