Question

if the volume of a given mass of a gas at STP is 52m³ what will be its volume at pressure of 104cmHg temperature remaining constant.

explain​

Answer 1

Answer:

Given,

At S.T.P,

Volume 1 (V₁) = 52 m³

Temperature 1 (T₁) = 273 K

Pressure 1 (P₁) = 76 cm of Hg

= 0.76 m of Hg

Pressure 2 (P₂) = 104 cm of Hg

= 1.04 m of Hg

Temperature remains constant,

According to Boyle's Law,

P₁V₁ = P₂V₂

= (0.76*52) = (1.04*V₂)

= 39.52 = 1.04V₂

= 38 m³ = V₂

The New Volume is 38 m³.

I hope this helps.