Question

If the volume of a given mass of a gas is doubled without changing its temperature, the pressure of the gas is reduced to.
a) 1/2 of the initial value
b) 1/3 of the initial value
c) 1/3 of the initial value
d) 2/3 of the initial value​

Answer 1

$\: \huge{\underline{\mathfrak\red{❥answer❣}}}$

1/2 of the initial value.

hope it was helpful to you

mark me brainlist please

Answer 2

Explanation:

Correct option is

C

increase four-fold

We know that

T

1

P

1

V

1

=

T

2

P

2

V

2

Volume of the gas = v

Pressure P

1

= p

Pressure P

2

=

2

1p

Temperature = T

1

= t

Temperature = T

2

= 2t

V

2

= P

1

V

1

T

2

/T

1

= (p×v×2t) / (2t×p)

= v

That means V

2

=V

1

So it increases four-fold so C is the correct option.