Question

if the volume of a given massof a gas at STP is 52 m³. What will be its volume at the pressure of 104 cm Hg and temperature remaining constant​

Answer 1

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if the volume of a given massof a gas at STP is 52 m³. What will be its volume at the pressure of 104 cm Hg and temperature remaining constant

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Use Boyle's law

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P1 x V1 = P2 x V2

Put the values from the queations

98 x 260 = 50 x V2

= 98*260/50V2

= 509.6 ml

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Answer 2

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Given :-

☆volume of given mass of a gas at STP is 52 cubic metre what will be its volume at the pressure of 104 CM of HG temperature remaining constant

Solution :-

P₁V₁ = P₂V₂

(100)(52) = (138.32)(V₂)

5200 = 138.32V₂

5200/138.32 = V₂

37.5 = V₂

The volume of the gas decreases is 37.5 m³.