Question

if the volume of a right circular cone of height 9 cm is 150.72cm^3 find the diameter of its base​

Answer 1

Answer:

Explanation:

Given :

• Height of a right circular cone (h) = 9 cm
• Volume of a right circular cone (V) = 150.72 cm³

To Find :

• The diameter of its base.

Solution :

Formula for"Volume of cone" is given as,

=> V = ¹/3 × πr²h

According to the question,

=> 150.72 = ¹/3 × 3.14 × r² × 9

=> 150.72 = 1 × 3.14 × r² × 3

=> 150.72 = 9.42 × r²

=> r² = 150.72/9.42

=> r² = 16.0

=> r = √16.0

=> r = 4.0 cm

Now,

Diameter = 2 × r

=> D = 2 × 4.0

=> D = 8.0 cm

Hence :

The diameter of its base is 8.0 cm.

Answer 2

$\huge\boxed{\underline{\mathrm{\red{A}\green{N}\purple{S}\orange{W}\blue{E}\pink{R}}}}$

$\rm\underline{\underline{\red{GIVEN :}}}$

$\green\bigstar$ Height of a right circular cone (h) = 9 cm.

$\green\bigstar$ Volume of a right circular cone = 150.72 cm³.

$\rm\underline{\underline{\purple{TO \: FIND :}}}$

$\orange\bigstar$ Find the diameter of its base.

$\rm\underline{\underline{\blue{SOLUTION :}}}$

$\pink\bigstar$ Volume of cone = 1/3 × πr²h

Now put the values,

$→150.72 = \frac{1}{3} \times 3.14 \times {r}^{2} \times 9$

$→150.72 = 1 \times 3.14 \times {r}^{2} \times 3$

$→150.72 = 9.42 \times {r}^{2}$

$→ {r}^{2} = \frac{150.72}{9.42}$

$→ {r}^{2} = 16.0$

$→r = √16.0$

$→r = 4.0 \: cm$

$\pink\bigstar$ Diameter = 2 × r

$→Diameter = 2 \times 4.0$

$→Diameter =\small\boxed{{\rm\pink{ \: 8.0 \: cm \: }}}$

$\small\boxed{{\rm\pink{Hence, \: the \: diameter \: of \: its \: base \: is \: 8.0 \: cm.}}}$

Hope it Helps Buddy ♥️

$\huge\bf{{\orange{★}}{\blue{★}}{\purple{★}}{\green{★}}{\pink{★}}{\color{red}{★}}{\color{gold}{★}}{\color{blue}{★}}{\color{gray}{★}}{\color{green}{★}}}$