Question

If the volume of a right circular cone of height 9cm is 48πcm cube,find the diameter of its base?

Answer 1

Answer:

volume of the rt circular cone=

1/3πr^2 h=48π

r2=48πx 3/πx 9 = 16

r=v16=4

diameter=2x4=8cm

Answer 2

${\huge{\pink{\underline{\underline{\tt{\blue{Hey \: Mate!}}}}}}}$

Let the radius of the base of the right circular cone be r cm

h = 9cm

Volume = 48πcm³

$\dfrac{1}{3}$ πr²h = 48π

$\dfrac{1}{3}$r²h = 48

$\dfrac{1}{3}$ × r²h × 9 = 48

r² = $\dfrac{48×3}{9}$

r² = 16

r = √16

4cm

2r = 2(4) = 8cm

$\sf\orange{Hence, \: the \: diameter \: of \: the \: base \: of \: the \: right \: circular \: cone \: is \: 8cm}$

$\large\fbox\fcolorbox{red}{plum}{\color{navy}{Hope \: It \: Helps \: You}}$