Question

if the volume of a sphere is increased by1525/16 percent without changing the shape what will e the percentage I crease in surface area

Answer 1

H1525/1600 = k.= 0.953…

(1+k) = 1.953…

Initial radius = r

Final radius = R

(Final / initial) volume =(R/r)^3 = (1+k)

(Final / initial) surface area =(R/r)^2 =(1+k)^(2/3)

= 1.953^(2/3)= 1.562