Question

If the volume of closed vessel in which the following simple reaction is carried out is reduced to one third of Original volume the rate of reaction becomes
2NO + O2 gives 2NO

Answer 1

Answer:

from the law of mass action consider given equation

2NO+O2=2NO2

So the volume of the simple reaction is equal to one third of the original volume.

rate=k*$[NO]^{2} [O_{2} ]$

If the volume is diminished to one third then concentration of both NO and O2 will becomes three times the rate of reaction increases 27 times.

Answer 2

For a given reaction,

Rate of reaction = k[NO]²[O2]

Rate of reaction is directly proportional to concentration of the compound or inversely proportional to the volume of the vessel.

C proportional to n/V

If volume of vessel is reduced by 1/3rd of its original value, then concentration of compound is increased by 3 times and consequently the rate of reaction by 27 times.

i.e, Rate= k[3NO]²[3O2] = k×9×3[NO]²[O2]

Rate = 27 times.

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