Question

if the volume of given mass of a gas at STP is 52 cubic metre what will be its volume at the pressure of 104 CM of HG temperature remaining constant
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Answer 1

Answer:-

Given:-

Initial volume of a gas at STP (V₁) = 52 m³

Initial pressure of a gas at STP (P₁) = 100 kPa (approx.)

Final Pressure of the gas (V₂) = 104 cm of Hg = 104 × 1.33 kPa = 138.32 kPa

We know that,

Boyle's law of gases states that at constant temperature, the pressure of a gas is inversely proportional to the volume.

i.e.,

⟹ P ∝ 1/V

⟹ PV = constant

⟹ P₁V₁ = P₂V₂

⟹ (100)(52) = (138.32)(V₂)

⟹ 5200/138.32 = V₂

⟹ 37.5 m³ = V₂

∴ The volume of the gas decreases to 37.5 m³.

Answer 2

Given :-

volume of given mass of a gas at STP is 52 cubic metre what will be its volume at the pressure of 104 CM of HG temperature remaining constant

Solution :-

P₁V₁ = P₂V₂

(100)(52) = (138.32)(V₂)

5200 = 138.32V₂

5200/138.32 = V₂

37.5 = V₂

The volume of the gas decreases is 37.5 m³.