Question

If the volume of the cylinder is 10m^3 and we fill it with 10 kg of oxygen then what is the volume of oxygen in the cylinder?Give reason.
plz help​

Answer 1

Answer:

Volume of oxygen, V1= 30 litres =30×10−3m3 

Gauge pressure, P1= 15 atm =15×1.013×105Pa

Temperature, T1=27oC=300K

Universal gas constant, R=8.314Jmol−1K−1

Let the initial number of moles of oxygen gas in the cylinder be n1 .

The gas equation is given as:

P1V1=n1RT1

∴n1=P1V1/RT1

=(15.195×105×30×10−3)/(8.314×300)=18.276

But n1=m1/M

Where, 

m1= Initial mass of oxygen 

M = Molecular mass of oxygen = 32 g

∴m1=N1M=18.276×32=584.84g

After some oxygen is withdrawn from the cylinder, the pressure and temperature reduces.

Volume, V2= 30 litres =

Answer 2

Explanation:

Number of moles of oxygen in the cylinder

=

Molecularmassingram

Massingram

=

32

2.5×10

4

=781.25

Number of moles of N

2

=3×781.25=2343.75

Mass of nitrogen in the cylinder =2343.75×28

=65625g

=6.5625×10

4

g

Total mass of the gas in the cylinder =2.5×10

4

+6.5625×10

4

=9.0625×10

4

g