If the volume of the small cube is 729 cm3. Eight such cubes are arranged to form a bigger cube. What would be the area of one of the faces of the bigger cube?
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Answer:
Volume =729 cm^3
Therefore, Side = 3√volume =3√729 = 9cm
Therefore, area of one side = (side)^2
(9)^2 = 81 cm^2
Therefore, area of one face of the bigger cube =
81 cm^2 ×8 =648 cm^2
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