If the voulme of a sphere and cube are equal are equal. Find the ratio of their total surface area
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GIVEN: Volume of a sphere = Volume of cube
TO FIND:
Total surface area of sphere / TSA of cube =?
OR (4Pi r²) / (6a²) =?
Volume of a sphere = (4/3) pi r^3 (r= radius of the sphere)
Volume of a cube = a^3 ( a= side of the cube)
(4/3) pi r^3 = a^3
=> r^3 / a^3 = 3/(4pi)
=> r/a = [3/(4pi)] ^1/3 …………..(1)
(4 pi r²) / (6a²)
= [4pi (3)^1/3 * (3)^1/3] / [6*(4pi)^1/3 * (4pi)^1/3]
= [4pi(9)^1/3] / [6*(4pi*4pi)^1/3 ]
Now by rationalizing the denominator by multiplying by (4pi)^1/3
=[ 4pi *(9)^1/3 *(4pi)^1/3] / [6*4pi]
= [(36pi)^1/3] / 6
Or, [cube root of 36pi] / 6 ……….ANS
TO FIND:
Total surface area of sphere / TSA of cube =?
OR (4Pi r²) / (6a²) =?
Volume of a sphere = (4/3) pi r^3 (r= radius of the sphere)
Volume of a cube = a^3 ( a= side of the cube)
(4/3) pi r^3 = a^3
=> r^3 / a^3 = 3/(4pi)
=> r/a = [3/(4pi)] ^1/3 …………..(1)
(4 pi r²) / (6a²)
= [4pi (3)^1/3 * (3)^1/3] / [6*(4pi)^1/3 * (4pi)^1/3]
= [4pi(9)^1/3] / [6*(4pi*4pi)^1/3 ]
Now by rationalizing the denominator by multiplying by (4pi)^1/3
=[ 4pi *(9)^1/3 *(4pi)^1/3] / [6*4pi]
= [(36pi)^1/3] / 6
Or, [cube root of 36pi] / 6 ……….ANS
Answered by
2
Hi there!
Let r and a be the radius of the sphere and edge of the cube respectively.
Given,
Surface area of sphere = Surface area of cube
4πr² = 6a²
(r/a)² = 3 / 2π
r / a = √(3/2π)
Volume of sphere / Volume of cube = (4/3)πr³ /a³
= (4π/3)(r/a)³
= (4π/3)[√(3/2π)]³
= (4π/3)(3/2π)[√(3/2π)]
= 2√(3/2π)
= √(4x3/2π)
= √(6/π)
Thus, Volume of sphere : Volume of cube = √6 : √π
Cheers!
Let r and a be the radius of the sphere and edge of the cube respectively.
Given,
Surface area of sphere = Surface area of cube
4πr² = 6a²
(r/a)² = 3 / 2π
r / a = √(3/2π)
Volume of sphere / Volume of cube = (4/3)πr³ /a³
= (4π/3)(r/a)³
= (4π/3)[√(3/2π)]³
= (4π/3)(3/2π)[√(3/2π)]
= 2√(3/2π)
= √(4x3/2π)
= √(6/π)
Thus, Volume of sphere : Volume of cube = √6 : √π
Cheers!
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