Question

if the wavelength is 6500 amstrong slit width is 0.55 mm and D=2m. Find 1) linear value of central maxima 2) angular position of 3rd minima and 3) distance of 2nd minima from central maxima?

Answer 1

Distance between the first 2 minimum on other

side =

d2λD=2×10−1×10−32×5×103×10−10×2=10×10−410−7=10−2m

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Answer 2

Answer :

(1). Linear value of central maxima = D * Width

→ Linear value of central maxima = 2 * 0.55

→ Linear value of central maxima = 1.10

(2). Angular position = 2λ

→ Angular position = 2 * 6500

→ Angular position = 13000

(3). Distance between the first 2 minimum on other

side =  D * 2λD

       =2 * 10 - 1 * 10 - 32 * 5 * 103 * 10 - 10 * 2

       =10 * 10 - 410 - 7

       =10 - 2

       = 8 m