Question

If the wavelength of an electromagnetic radiation is
300 nm then the energy of a photon (in joule) will be
(h = 6.63 x 10-34 Js, speed of light (c) = 3 * 108 ms-')
(1) 6.63 10^-18 (2) 6.63 x 10^17
(3) 6.63 * 10-^19
(4) 6.63 x 10^16
​

Answer 1

Answer: Answer is option no. 3

Explanation:

Wavelength= 300 * 10^-9 m

Also we know that

E= hc/λ

  Therefore substituting the values of h , c, λ

    E= 6.63*10^-34 * 3*10^8/ 300*10^-9

      = 6.63*10^-19 J

Please mark as brainliest. I hope it helps.