Question

if the wavelength of light is 5.8X10^-5 cm, what will be the energy in one proton in the given region of light​

Answer 1

Answer:

E = 3.427 x 10⁻¹⁹ J = 2.13 eV.

Explanation:

Energy of photon(E) is given by hc/λ.

Here h is planck's constant and its value is 6.625 x 10⁻³⁴ J-s.

c is speed of light and is given by 3 x 10⁸ m/s.

λ is the wavelength of the light used. Given that it is 5.8 x 10⁻⁵ cm.

That can be written as 5.8 x 10⁻⁷ m.

∴ E =  6.625 x 10⁻³⁴  x 3 x 10⁸/ 5.8 x 10⁻⁷

 E = 3.427 x 10⁻¹⁹ J.

It is ridiculously small. It can be converted to smaller unit 'electron-volts(eV)' by dividing with 1.602 x 10⁻¹⁹.

E = 3.427 x 10⁻¹⁹/1.602 x 10⁻¹⁹

E = 2.13 eV.