If the weight of 3bags of grains is 93 kg,then341kg is the weight of how many bags of grains
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Answer:
Step-by-step explanation:
sum of three bags =93
sum of n bags = 341
so s3= n/2 (2a+(n-1)d)
93= 3/2 (2a+(n-1)d)
93/3 = 1/2 (2a+(n-1)d = 1/2 (2a+(3-1)d
31 =1/2 ×2 (a + d)
31 = a+d
similarly
341×2 = n (2a + dn - d)
682= n (2(31-d) + dn -d
682 = n ( 62 - 3d + dn)
682 = 62n -3dn + dn^2
then solve by splitting middle term method
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