Question

If the weight of dry raisins is W1 and that of soaked raisins is W2 ,then the correct equation for calculating the percentage of water absorbed by raisins will be (1) W1-W2
(2) W2-W1
(3) W2-W1W1×100
(4) W1-W2W2×100

Answer 1

The percentage of water absorbed by raisins are $(\frac{W_{2}-W_{1}}{W_{1}})\times 100$.

Explanation:

1. Here

Dry weight of raisins = $W_{1}$

Wet weight of raisins = $W_{2}$

2. So

  weight of water absorbed by raisins = Increase in weight of raisins  = $W_{2}-W_{1}$

3. Now percentage of water absorbed by raisins = $\frac{Increase in weight of raisins}{initial weight of raisins}$

4. So percentage of water absorbed by raisins = $(\frac{W_{2}-W_{1}}{W_{1}})\times 100$