Question

If the weight of metal oxide is x g containing yg of
oxygen, the equivalent weight of metal will be
8x
(1) E=
y
(2) E= 8(y - x)
Х
(3) E-Y
8(x-y)
(4) E=
у​

Answer 1

Answer:

Mass of the metallic oxide =

1

g

; mass of the metal =

0.68

g

Mass of oxygen = mass of oxide - mass of metal

Mass of oxygen

=

1

–

0.68

=

0.32

g

Using the oxygen displacement method,

weight of the metal

weight of oxygen

=

equivalent weight of the metal

equivalent weight of oxygen

Equivalent weight of metal

=

0.68

0.32

×

8

=

17

g