Question

if the weight of metal oxide is xg containing yg of oxygen the equivalent weight of metal will be​

Answer 1

Answer:

wt of metal oxide= x

wt of oxygen = y

so, wt of metal = x-y

so equivalent wt of metal is the no of parts of metal reacted with 16 gram of oxygen....so

y gm oxygen is reacted with= x-y gm metal

1 gm oxygen is reacted with=x-y/y

so

16 gm oxygen is reacted with = x-y×16/y

so equivalent wt of metal= 16(x-y)/y...ans

Explanation:

Answer 2

Answer:(x/y)×8

Explanation:r