If the width of a rectangle is increased by 25% while the length remains constant, the resulting area is what percent of the original area?
Anonymous:
125%
sorry
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the area is 125 percent of original area
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Let the length , width and area of rectangle be L,B,A respectively.
Now, As we know,
Area of rectangle i.e. A= L*B.
Here,
Width increase by 25% ,
So, New width = B+ 25% of B = B+ B/4 = 5B/4
New Area = L * 5B/4 = 5/4 * LB
i.e. New area is 5/4 times of old area,
which means resulting area is 5/4 *100= 125% , of original area.
Now, As we know,
Area of rectangle i.e. A= L*B.
Here,
Width increase by 25% ,
So, New width = B+ 25% of B = B+ B/4 = 5B/4
New Area = L * 5B/4 = 5/4 * LB
i.e. New area is 5/4 times of old area,
which means resulting area is 5/4 *100= 125% , of original area.
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