Question

if the window of the house is 3m above the ground then the distance of the point c from d is​

Answer 1

Answer:

6

Explanation:

If the window of the house is 3m above the ground then the distance of the point c from d is​ 6.

Hence the answer is for this question is 6.

Answer 2

Given: ladder touches the wall at a distance of $4m$ above ground when it is placed at a distance of $3m$. Then it is inclined to the window and the distance of window from ground is $3m$.

To find: distance prom C to D.

Step-by-step method:

Step 1 of 2

The length of the ladder is not changing it is constant so, $AC=CE$.

Both the triangles are right angled triangles, we can apply Pythagoras theorem to both of them.

In Δ$ABC$,

$AB^{2} +BC^{2} =AC^{2} \\4^{2}+3^{2}=AC^{2}\\16+9=AC^{2}\\25=AC^{2}\\AC=5m$

Step 2 of 2

In Δ$CDE$,

$CD^{2}+DE^{2}=CE^{2}\\CD^{2}+3^{2}=5^{2}\\CD^{2}=25-9\\CD^{2}=16\\CD=4m$

The distance of point C from D is $4m$.