If the wire of length 2 m and area of cross section 2 mm2 has resistivity of 20 × 10-12 Ω m, find its resistance
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Answer:
Explanation:
LENGTH ,L = 2 M
AREA = 2 MM²
= 2*(10⁻³)²
= 2*10⁻⁶ M²
RESISTIVITY ,ρ = 20*10⁻¹² OHM M
RESISTANCE , R =?
FORMULA:
RESISTANCE = RESISTIVITY *LENGTH/AREA
R = ρ *L/A
R = 20*10⁻¹²*2/2*10⁻⁶
R = 20*10⁻¹²*10⁶
R = 20*10⁻⁶
R = 2*10⁻⁵ OHMS.
RESISTANCE OF THE WIRE = 2*10⁻⁵ OHMS.
HOPE THIS HELPS.
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