Math, asked by Sput, 1 year ago

If the words formed by using the letters of the word AGAIN are arranged in the form of dictionary then 50th word is

Answers

Answered by nikitajha400
2

Characters in ascending order={A,G,I,N}

Number of words starting with A =4!=24=4!=24
Number of words starting with G =4!2!=12=4!2!=12
Number of words starting with I =4!2!=12=4!2!=12
Total numbers uptill now=48

49th word=NAAGI

50th word=NAAIG
Answered by snehitha2
3
{AGAIN}

write in alphabetical order,l

A,G,I,N

Number of words starting with letter A:-

4! = 4×3×2×1 = 24

Number of words starting with letter G:-

4!/2! = 4×3×2!/2! = 12

Number of words starting with letter I:-

4!/2! = 4×3×2!/2! = 12

Total number of words till now :-

= 24+12+12 = 48

49th word which starts with letter N in the dictionary is

NAAGI

50ty word which starts with letter N in the dictionary is

NAAIG

Hope it helps...
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