If the work done by a force in moving an object through a distance of 20 cm is 24.2 J, what is the magnitude of the force?
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Answered by
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Answer:
Work done = 24.2 J
Distance = 20 cm
= 20/100 m
= 1/5 m
= 0.2m
Force = ?
work = force x displacement
force = work / displacement
force = 24.2/(1/5)
= 24.2 × 5
= 121 N
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