If the work done by a motor to lift a 200 kg block to a
height h is 30 kJ, then calculate the value of height
(h) in metres (Take, g= 10 m/s2).
Answers
Explanation:
By work-energy theorem,
W=ΔP.E.
=> W=P.E. (Assuming initial P.E.=0)
=> W=mgh
=>h= W/mg
Putting the values...
h=30,000 J/ 200kg×10 m/s²
= 15 m
Given : work done by a motor to lift a 200 kg block
to a height h is 30 kJ
To Find : calculate the value of height (h) in metres (Take, g= 10 m/s2).
Solution:
Work done by motor = mgΔh
m = 200 kg
g = 10 m/s²
Δh = h m
Work done = 30 kj = 30 x 10³ joule
=> 30 x 10³ = 200 * 10 * h
=> 30 x 10³ = 2 x 10³ * h
=> 30 = 2 h
=> 15 = h
value of height (h) in metres = 15 m
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