If the work done by the force in moving an object through a distance of 20cm is 24.2j then what is the magnitude of the force? Answer step wise.
Answers
Answered by
124
work done = 24.2 J
distance = 20 cm
= 20/100 m
= 1/5 m
force = ?
--------------------------------------------------------------------------------------------------
we know
work = force x displacement
force = work / displacement
force = 24.2/ (1/5)
= 242 x 5/10
= 121.0 N
= 121 N
distance = 20 cm
= 20/100 m
= 1/5 m
force = ?
--------------------------------------------------------------------------------------------------
we know
work = force x displacement
force = work / displacement
force = 24.2/ (1/5)
= 242 x 5/10
= 121.0 N
= 121 N
Calisto1:
it is wrong the answer is 121n
corrected
thank u :)
Answered by
94
Work done = 24.2 J
Distance = 20 cm
= 20/100 m
= 1/5 m
= 0.2m
Force = ?
work = force x displacement
force = work / displacement
force = 24.2/(1/5)
= 24.2 × 5
= 121 N
Distance = 20 cm
= 20/100 m
= 1/5 m
= 0.2m
Force = ?
work = force x displacement
force = work / displacement
force = 24.2/(1/5)
= 24.2 × 5
= 121 N
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