Question

If the work function of a certain metal is \text{3}\text{.2}\times \text{1}{{\text{0}}^{\text{-19}}}j3.2×10-19jand it is a illuminated with light of frequency \text{8}\times \text{1}{{\text{0}}^{\text{14}}}\text{Hz,}8×1014Hz, the maximum kinetic energy of photo electrons would be\text{(h = 6}\text{.6}\times \text{1}{{\text{0}}^{\text{-34}}}\text{Js)}(h = 6.6×10-34Js)____​

Answer 1

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Answer 2

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This question is not understandable...