Question

If the work function of a metal is '∅ ' and the frequency of the incident light is 'ν' , there is no emission of photoelectron if
(a) $\nu\ \textless \ \frac{\phi}{h}$
(b) $\nu= \frac{\phi}{h}$
(c) $\nu\ \textgreater \ \frac{\phi}{h}$
(d) $\nu\ \textgreater \ =\ \textless \ \frac{\phi}{h}$

Answer 1

It should be more than work function for ejection of electrons so option a) is correct

@skb