Question

If the work function of metal is 3.4 eV and the kinetic
energy of ejected electron is 1.6 eV then the energy of
radiation falling on the metal surface is​

Answer 1

I think it would be the answer

Answer 2

Answer:

The energy of the radiation, E, falling on the metal surface measured is $5eV$.

Explanation:

Given,

The work function of the metal, Ф = $3.4eV$

The ejected electron's kinetic energy, $K.E$ = $1.6eV$

The energy of the radiation falling on the metal surface, E =?

As we know,

• ​According to the equation of photoelectric effect:
• K.E = $E - \phi$

After putting the given values in the equation, we get:

• $1.6eV = E - 3.4eV$
• E = $1.6eV + 3.4eV$
• E = $5eV$

Hence, the energy of the radiation falling on the metal surface, E = $5eV$.