Question

If the yield of given reaction is 33.33%, what volume of O2 gas will be produced if 4 moles of K,C1,0, are taken initially: K,C1,0, _- >K,C104 +C1,0, +0, (unbalanced)​

Answer 1

Explanation:

The balanced chemical equation is as follows:

2KClO3(s) = 2KCl(s) + 3O2(g)

2 moles of KClO3 = 2(39+35.5+3×16)g

= 245g

3 moles of O2 gas = 3×22.4 L(at STP)

By the decomposition of 245g of KClO3 the volume of O2 gas liberated 3×22.4L

So,…………………..45g…………………………3×22.4×45/245

= 12.34L