If the young's modulus of a material is twice the modulus of rigidity , the poission's ratio of the material is
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The answer is zero.
Explanation: the relation between poisson's ratio, modulus of elasticity and modulus of rigidity is
E= 2G(1+Mu)
where, Mu- poisson's ratio.
E- modulus of elasticity.
G- Modulus of rigidity.
Now according to the question, E= 2G
=> 2G =2G(1+Mu)
=> 1 = 1+Mu
=> Mu = 0.
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Answer:f the Young's modulus of elasticity of a material is twice its modulus of rigidity, then compute the Poisson's ratio of material.
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