Question

if the zero of a polynomial K - 1 X square + kx + 1 is minus 3 find the value of k​

Answer 1

Answer:

let p(x)=k-1x square +kx+1

g(x)=-3

g(x)=0

x=3

k-1*3square+k*3+1

k-9+3k+1

k-8+3k

4k-8=0

4k=8

k=8/2

k=4

consider *as multiplication sign

Answer 2

Step-by-step explanation:

GIVEN:-)

→ One zeros of quadratic polynomial = -3.

→ Quadratic polynomial = ( k - 1 )x² + kx + 1.

Solution:-

→ P(x) = ( k -1 )x² + kx + 1 = 0.

→ p(-3) = ( k - 1 )(-3)² + k(-3) + 1 = 0.

=> ( k - 1 ) × 9 -3k + 1 = 0.

=> 9k - 9 -3k + 1 = 0.

=> 6k - 8 = 0.

=> 6k = 8. .....

$\large \boxed{=> k = \frac{8}{6} = \frac{4}{3} }$

Hence, the value of ‘k’ is founded .