Question

If the zero of polynomial (k-1)x^2+kx+1 is -3 find value of k

Answer 1

Answer:

k=4/3

Step-by-step explanation:

p(x)=(k-1)x^2+kx+1

p(-3)=(k-1)(-3)^2+k(-3)+1

0=(k-1)(9)-3k+1

9k-9-3k+1=0

6k=8

k=8/6

k=4/3

Answer 2

(k-1)x^2+kx+1 is -3

p[3]= 3-1 *3^2+ 3*3+1

=2*9+9+1

18+10

28

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