Question

if the zero of the polynomial 2xsquare-3x+p is 3 , then the other zero and the value of p is what​

Answer 1

Answer:

( p(x)=2 x^{2}-3 x+p=0 ) ( p(3)=2(3)^{2}-9+p=0 ) ( p=-9 ) ( 2 x^{2}-3 x+9=0 ) ( 2 x^{2}-6 x+3 x-9=0 ) ( (2 x+3)(x-3)=0 ) Other ( 2 e r 0=frac{-3}{2} ) value of ( p=-9 )

Answer 2

Answer:

First, chose one of the variables to isolate.

In this case, let’s isolate x . In order to do so, we need to cancel out the y variable. Multiply the first equation by 2 and the second by 3 to get the following:

4x−6y=22

15x+6y=54

Now adding both equations would rid us of the y variable to get:

19x=76 hence x=4

Now replace x by 4 in any of the original equations:

5(4)+2y=18

20+2y=18

2y=−2

y=−1

So the answer to the equations is 4;−1