Question

if the zero of the polynomial x3-3x2+x+1 are a-b,a,a+b​

Answer 1

Step-by-step explanation:

We have ,

sum of zeros = a-b+a+b+a=3

→3a=3→a=1

Product of zeros=(a-b)(a+b)a=-1

→(a^2-b^2)1=-1

→1-b^2=-1

→b=√2 or ,-√2

Answer 2

Step-by-step explanation:

We have ,

sum of zeros = a-b+a+b+a=3

→3a=3→a=1

Product of zeros=(a-b)(a+b)a=-1

→(a^2-b^2)1=-1

→1-b^2=-1

→b=√2 or ,-√2

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