Question

if the zero of the quadratic polynomial x2+(a+1)x+b are 2 and -3 then​

Answer 1

Answer:

sorry I can't understand your question

I think it's incomplete

Answer 2

Answer:

Step-by-step explanation:

Answer

5.0/5

1

Brainly User

Answer:

If the polynomial is x2 + 5, then to calculate the zeroes you would write:

x2 + 5 = 0

which leads to

x2 = -5

which yields solutions

x = +/- i√5 where i = √-1

We are to calls these zeroes α and β. So, α = i√5 and β = -i√5.

We now want to form a polynomial with roots 1 + α and 1 + β. This yields the equation,

[x - (1 + α)][x - (1 + β)] = 0

Multiplying we get

x2 -(1 + β)x - (1 + α)x + (1 + α)(1 + β) = 0

or

x2 - (2 + α + β)x + (1 + α)(1 + β) = 0

or

x2 - (2 + i√5 - i√5) + (1 + i√5)(1 - i√5) = 0

or

x2 - 2x + 6 = 0