Question

If the zero's of the polynomial x^2-8x+k=0 are the H.C.F of (6,12) , then find the value of k

Answer 1

Answer:

k=12

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Answer 2

Answer:

The answer is 12.

Step-by-step explanation:

The HCF of 12 and 6 is 2X3 which is 6. Now when we substitute x with 6 (on both places) the value we get for k is 12.

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