Question

if the zeroes of a quadratic polynomial p(x) = ax^2+x+a are equal then the value of a is (a)1/2(b)−1/2(c)±1/2(d)±1

Hmm
How to on liv e cha t?​

Answer 1

Answer:

c)

Explanation:

Here

A=a   B=1   C= a

Discriminant d=b^2 - 4ac

But as zeros are equal

discriminant should be zero

∴$b^{2}$-4ac = 0

1-4(a)(a)=0

4(a)(a)=1

(a)(a)=$\frac{1}{4}$

a=±$\frac{1}{2}$

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Answer 2

bhai kya thu free fire keleta hai