Question

if the zeroes of p(x)=x2 + (a+1) x+b are 2 and -3 then a, b is​

Answer 1

Answer:

$\alpha = 2 \: and \: \beta = - 3 \\ \alpha + \beta = - (a + 1) \\ 2 - 3 = - a - 1 \\ - 1 = - a - 1 \\ a = 0 \\ \alpha \beta = b \\ 2 \times - 3 = b \\ b = - 6$