Question

if the zeroes of polynomial p(x)=x³-12x²+39x+28 are a;a+b;a+2b find all the zeroes
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Answer 1

Step-by-step explanation:

Q:p(X)=x³-21x²+39x-28

A:Let the zeroes be:-

a-d,a,a+d

a-d+a+a+d=12.

3a=12

a=4

a(a+d)(a-d)=28

a(a²-d²)=28

4(16-d²)=28

16-d²=7

-d²=-9

d=3

⏺️a-d=1

⏺️a = 4

⏺️a+d=7

ANS:- The ZEROES are:-1,4,7

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