Question

If the zeroes of polynomial x^2+(a+1)x+b are 2 and -3, then find the value of a and b.

Answer 1

Hii friend,

P(X) = X²+(A+1)X + B

A = 1 , B = A+1 , C = B

2 and -3 are the two zeros of the polynomial X²+(A+1)X+B

Let alpha = 2 and Beta = -3

sum of zeros = - B/A

(Alpha + Beta) = -A+1/1

2 + (-3) = -A+1/1

2-3 = -A+1

-A+1 = -1

-A = -1-1

-A = -2

A = 2

And,

Product of zeros = C/A

Alpha × Beta = B/1

2 × -3 = B/1

-6 = B

B = -6

Hence,

A = 2 and B = -6

HOPE IT WILL HELP YOU..... :-)