Question

If the zeroes of polynomial x^3 - 3x^2 + x + 1 are (a-b) ,a, (a+b), then find the value of a and b.

Answer 1

HEYA !!!!!!!!!!!!

x³-3x²+x+1

The zeroes of the polynomial are (a+b),a, (a-b)  

Let α=a-b

β=a

γ=a+b

α+β+γ=-x² coefficient/x³ coefficient  

a-b+a+a+b=-3/1

3a=-3

a=-3/3

a= -1

αβγ= -constant/x³ coefficient  

(a-b)(a)(a+b)=-1/1

(a²-b²)(a)= -1

[(-1)²-b²](-1)=-1

(1-b²)= -1/-1

1-b²=1

1-1=b²

b²=0

b=√0=0

Therefore, a=-1 and b=0

Hope it helps ....